SSC CGL 2022 PYQ — Question 93

SSC CGL - 18 April 2022 - Shift 1 • Reasoning • Q93

In a certain code language ‘ROUBST’ is coded as 61. How will ‘FORTUNATE’ be coded in that language?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 114.

The logic used here is:

‘ROUBST’ is coded as 61

Opposite of R = I = 9

Opposite of O = L = 12

Opposite of U = F = 6

Opposite of B = Y = 25

Opposite of S = H = 8

Opposite of T = G = 7

ROUBUST = (9 + 12 + 6 + 25 + 8 + 7) - Number of letters in the word = 67 - 6 = 61

Similarly;

Code for the word FORTUNATE:

Opposite of F = T = 21

Opposite of O = L = 12

Opposite of R = I = 9

Opposite of T = G = 7

Opposite of U = F = 6

Opposite of N = M = 13

Opposite of A = Z = 26

Opposite of T = G = 7

Opposite of E = V = 22

FORTUNATE = (21 + 12 + 9 + 7 + 6 + 13 + 26 + 7 + 22 ) - Number of letters in the word = 123 - 9 = 114

Hence, option 4 is the correct answer.