In a △ ABC , right anged at B, if tan A = 1/(√(3)) , then sin A.cos A+cos A.sin C=

In a △ ABC , right anged at B, if tan A = 1/(√(3)) , then…

In a $\triangle ABC$ , right anged at B, if $\tan A = \frac{1}{\sqrt{3}}$ , then $\sin A.\cos A+\cos A.\sin C=$

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Correct answer: D

Explanation

The correct answer is option 4 i.e. 1

In this triangle, sinA = cosC , because it is a complimentary pair.

Also, sinC = cosA

We can write the given equation as sinA.sinA + cosA.cosA = sin²A + cos²A = 1