In a ΔABC, D and E are two points on side AB and BC, respectively such that AD : DB = 2 : 3 and DE || AC. If the area of ΔBDE is equal to 18 cm2, then what is the area(in cm2) of ΔABC?
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. 50
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Concept |
Application |
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If all three angles of 2 triangles are equal, then these two triangles are similar triangles. And (Area of triangle1/ Area of triangle2) = (Side12/Side22) |
Given DE || AC Hence, triangle ABC and BDE will be similar. Hence, (Area of ΔABC/Area of ΔBDE) = (AB/BD)2 ⇒ Area of ΔABC/18 = (5/3)2 ⇒ Area of ΔABC = 25/9 × 18 = 50 |