SSC CHSL 2024 PYQ — Question 71

SSC CHSL - 09 July 2024 - Shift 1 • Quantitative Aptitude • Q71

In a 2 km linear race, if P completes the race in 200 second and Q in 220 seconds, then the distance by which P beats Q is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 1819119\over11 metres.

Length of the race = 2 km = 2000 m

Speed of P = 2000/200 = 10 m/s

Speed of Q = 2000/220 = (10/11) m/s

Time taken by P = 200 sec

Distance covered by Q in 200 seconds = (10/11) × 200 = (2000/11) meters

Distance by which P beats Q = Total race distance - Distance covered by Q

= 2000 - (2000/11)

= 181911181\frac{9}{11}meters

Therefore, P beats Q by 181911181\frac{9}{11} meters.