SSC CHSL 2024 PYQ — Question 66

SSC CHSL - 04 July 2024 - Shift 4 • Quantitative Aptitude • Q66

In a 100-meter race, A beats B by 20m and B beats C by 5m. In the same race, find the distance by which A beats C.

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 24 meters.

A beats B by 20 meters.

When A runs 100 meters, B runs 100 - 20 = 80 metre

Ratio of the distance covered by A and B = 100 : 80 = 5 : 4

B beats C by 5 meters.

When B runs 100m, C runs 100 - 5 = 95 meter

Ratio of the distance covered by B and C = 100 : 95 = 20 : 19

So, A : B : C = 25 : 20 : 19

Let A runs 25 units, B runs 20 units, and C runs 19 units.

If A runs 100 meter = (25 × 4)

Then, C runs 19 × 4 = 76 meter

Now, A beats C by 100 - 76 = 24 meter

Therefore, A beats C by 24 meters.