In 2019 if there is 10% increase in population of city A and 15% decrease in the population in B as compared to that in 2018, then the population of city A is what percentage more/less than that in B, in that year? (correct to one decimal places)
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 9.2% more.
The population of city A in 2018 = 54
Population of city B in 2018 = 64
Population of city A in 2019 = 54 × 110/100 = 59.4
Population of city B in 2019 = 64 × 85/100 = 54.4
The population of city A is more than that of B by = (59.4 – 54.4) / 54.4 × 100 = 9.2%