SSC CHSL 2023 PYQ — Question 75

SSC CHSL 2023 - 03 Aug 2023 - Shift 3 • Quantitative Aptitude • Q75

If (y+1y)=8(y+\frac{1}{y}) = 8, find the value of (y2+1y2)(y^2+\frac{1}{y^2}).

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 62.

Given that

(y+1y)=8(y+\frac{1}{y}) = 8

Calculation

Squaring both sides

⇒ (y2+1y2)(y^2+\frac{1}{y^2}) + 2 = 64

⇒ (y2+1y2)(y^2+\frac{1}{y^2}) = 64 - 2 = 62