SSC CHSL 2023 PYQ — Question 68

SSC CHSL - 10 Aug 2023 - Shift 2 • Quantitative Aptitude • Q68

If (y - 1y\frac{1}{y}) = 8, find the value of (y² + 1y2\frac{1}{y^2}).

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 66.

y - (1/y) = 8

⇒ (y - 1/y)2 = y2 - 2(y)(1/y) + (1/y)2 = 82

⇒ y2 - 2 + 1/y2 = 64

⇒ y2 + 1/y2 = 64 + 2 = 66

Therefore, the required value is 66.