If xSin3θ + yCos3θ = Sinθ Cosθ and xSinθ = yCosθ, then find the value of x2 + y2.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e 1
We have,
⇒ xSinθ = yCosθ
⇒ y = xTanθ
⇒ xSin3θ + yCos3θ = Sinθ.Cosθ
⇒ xSin3θ + (xTanθ)Cos3θ = Sinθ Cosθ
⇒ xSin2θ + xCos2θ = Cosθ
⇒ x = Cosθ
⇒ y = Sinθ & x = Cosθ
⇒ x2 + y2 = Sin2θ + Cos2θ = 1