If and x, y ≠ 0, then find the value of .
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 0.
⇒
⇒ x2 + y2 - xy = 0
⇒ = (x3 + y3)2
⇒ ((x + y)(x2 + y2 - xy))2 = 0 [(a3 + b3) = (a - b)(a2 + b2 - ab)]
SSC Selection Post - Matriculation Level 2022 - 9 Feb 2022 - Shift 1 • Quantitative Aptitude • Q71
If and x, y ≠ 0, then find the value of .
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 0.
⇒
⇒ x2 + y2 - xy = 0
⇒ = (x3 + y3)2
⇒ ((x + y)(x2 + y2 - xy))2 = 0 [(a3 + b3) = (a - b)(a2 + b2 - ab)]