If x4 + y4 = x2y2, then the value of x6 + y6 is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 0.
Given that
⇒ If x4 + y4 = x2y2
⇒ (x2 + y2)2 - 2x2y2 = x2y2
⇒ (x2 + y2)2 = 3x2y2
⇒ x2 + y2 = √ 3 xy .....(1
Cube both sides
⇒ (x2 + y2 )3 = (√ 3 xy)3
⇒ x6 + y6 + 3x2y2 (x2 + y2 ) = 3√ 3 x3y3
Put the value of x2 + y2 from equation 1
⇒ x6 + y6 + 3x2y2 (√ 3 xy ) = 3√ 3 x3y3
⇒ x6 + y6 + 3√ 3 x3y3 = 3√ 3 x3y3
⇒ x6 + y6 = 0