SSC CPO 2019 PYQ — Question 102

SSC CPO Tier I - 12th March 2019 - Shift 1 • Quantitative Aptitude • Q102

If x4 + x2y2 + y4 = (21/256) and x2 + xy + y2 = (3/16), then 2(x2 + y2) = 

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. (5/8)

x4 + x2y2 + y4 = x4 + 2x2y2 + y4 - x2y2

= (x2 + y2)2 - (xy)2

= (x2 + xy + y2) (x2 - xy + y2)

⇒ (3/16) (x2 - xy + y2) = 21/256

⇒ (x2 - xy + y2) = (21 × 16)/(256 × 3) = 7/16

⇒ (x2 - xy + y2) = 7/16

Given: x2 + xy + y2 = (3/16)

Adding both:

⇒ 2(x2 + y2) = 10/16 = 5/8