If x4 + x2y2 + y4 = (21/256) and x2 + xy + y2 = (3/16), then 2(x2 + y2) =
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Correct answer: B
Explanation
The correct answer is Option 2 i.e. (5/8)
x4 + x2y2 + y4 = x4 + 2x2y2 + y4 - x2y2
= (x2 + y2)2 - (xy)2
= (x2 + xy + y2) (x2 - xy + y2)
⇒ (3/16) (x2 - xy + y2) = 21/256
⇒ (x2 - xy + y2) = (21 × 16)/(256 × 3) = 7/16
⇒ (x2 - xy + y2) = 7/16
Given: x2 + xy + y2 = (3/16)
Adding both:
⇒ 2(x2 + y2) = 10/16 = 5/8