If x4 + x2y2 + y2 =21 and x2 + xy + y2 = 3 , then what is the value of (-xy)?
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Correct answer: B
Explanation
The correct answer is option 2 i.e. 2
Here it is given that,
x4 + x2y2 + y2 =21
On adding x2y2 on both sides we get,
x4 + x2y2 + y2 + x2y2 - x2y2 = 21
(x2 + y2)2 - x2y2 = 21
(x2 + y2)2 = 21 + x2y2 .................(1)
x2 + xy + y2 = 3
x2 + y2 = 3 - xy..................(2)
On putting the value of eq 2 in eq 1 we get,
9 + x2y2 - 6xy = 21 + x2y2
-6xy = 12
-xy = 2.