SSC CHSL 2021 PYQ — Question 53

SSC CHSL - 13 April 2021 - Shift 3 • Quantitative Aptitude • Q53

If x3 + y3 = 468 and x + y = 12, then the value of x4 + y4 will be:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 3026

x4 + y4 = (x2 + y2)2 - 2x2y2   ----(1)

x³ + y³ = (x + y) (x² + y² - xy)

46812\frac{468}{12} = (x² + y² - xy)   

39 = (x² + y² - xy)    -----(2)

(x+y)² = x² + y² + 2xy

144 = x² + y² + 2xy

x² + y² = 144 - 2xy    ------(3)

Putting x² + y² in eqn(2)

 39 = (144 - 2xy - xy)

We get xy = 35 & x² + y² = 74

Now,

x⁴ + y⁴ = (74)² - 2(35)²

⇒ 5476 - 2450

⇒ 3026