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SSC CGL 2018 PYQ — Question 81

SSC CGL Tier II Quant - 21/02/2018 • Quantitative Aptitude • Q81

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If x3 – 4x2 + 19 = 6(x – 1), then what is the value of [x2 + (1/x – 4)]?

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 6

x3 – 4x2 + 19 = 6(x – 1) .....(1)

x3 – 4x2 - 6x + 6 + 19 = 0

x3 – 4x2 - 1 = 6x - 24

By putting the value of (x3 – 4x2 - 1)

(6x - 24)/(x - 4) = 6(x - 4)/x - 4 = 6

x2 + 1/(x - 4) = 6