SSC CHSL 2025 PYQ — Question 58

SSC CHSL - 17 Nov 2025 - Shift 3 • Quantitative Aptitude • Q58

If x² + y² + z² = 2(5x + 6y + 4z) − 77, then find the value of 2(x + y) - 3z.

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Correct answer: C

Explanation

Has been given :

x² + y² + z² = 2(5x + 6y + 4z) − 77

According to the formula:

a² − 2ab = (a − b)² − b²

x² + y² + z² = 10x + 12y + 8z − 77

x² − 10x + y² − 12y + z² − 8z + 77 = 0

(x² − 10x + 25) + (y² − 12y + 36) + (z² − 8z + 16) = 0

(x − 5)² + (y − 6)² + (z − 4)² = 0

x = 5, y = 6, z = 4

2(x + y) − 3z

= 2(5 + 6) − 3(4)

= 22 − 12

= 10