SSC CHSL 2023 PYQ — Question 74

SSC CHSL - 08 Aug 2023 - Shift 2 • Quantitative Aptitude • Q74

If x2−55x+1=0x^2- 5\sqrt5 x + 1 = 0, and x > 0, what is the value of (x3−1x3)(x^3-{1\over x^3}) ?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 1364.

(a - b)3 = a3 - b3 - 3ab(a - b)

Given, x2−55x+1=0x^2- 5\sqrt5 x + 1 = 0

Dividing the given expression be x,

⇒ x+1x=55x + { 1 \over x} = 5\sqrt{5}

Now, (x−1x)2=(x+1x)2−4(x - { 1 \over x})^2 = (x + {1 \over x})^2 - 4

⇒ (x−1x)2(x - {1 \over x})^2 = 125 - 4

⇒ x−1xx - {1 \over x} = 11

Now, cubing both the sides, 

⇒ (x−1x)3(x - {1 \over x})^3 = 1331

⇒ x3−1x3x^3 - {1 \over x^3} - 3(11) = 1331

⇒ x3−1x3x^3 - {1 \over x^3} = 1331 + 33

⇒ x3−1x3x^3 - {1 \over x^3} = 1364