SSC CGL 2018 PYQ — Question 17

SSC CGL Tier II Quant - 20/02/2018 • Quantitative Aptitude • Q17

If x2 – 12x + 33 = 0, then what is the value of (x – 4)2 + [1/(x – 4)2]?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 (i.e. 14)

x2 – 12x + 33 = 0

(x – 4)2 –4 (x – 4) + 1 = 0

= 14