SSC CGL 2022 PYQ — Question 59

SSC CGL - 20 April 2022 - Shift 1 • Quantitative Aptitude • Q59

If x2 + 1x2\frac{1}{x^2}= 18, x > 0, then find the vale of x3 + 1x3\frac{1}{x^3}.

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 345\sqrt{5}

(a + b)2 = a2 + b2 + 2ab         ---- (1)

(a + b)3 = a3 + b3 + 3ab(a + b)       ----- (2)

Using equation (1), we get

⇒ (x + 1/x)2 = x2 + 1/x2 + 2

⇒ (x + 1/x)2 = 18 + 2 = 20

⇒ (x + 1/x) = 252\sqrt5

Using equation (2), we get

⇒ (x + 1/x)3 = x3 + 1/x3 + 3(x + 1/x)

⇒ 40√5 = x3 + 1/x3 + 6√5

⇒ x3 + 1/x3 = 34√5