If x, y, z are three integers such that x + y = 8, y + z = 13 and z + x = 17, then the value of x2/yz is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 18/11
| Application |
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Given: x + y = 8 ...........i) y + z = 13 ........ii) z + x = 17 .......iii) |
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y = 8 - x (from eq i) So, 8 - x + z = 13 (put the value of y) z - x = 5 ........iv) |
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Adding eq iii) and eq iv): ⇒ 2z = 22 ⇒ z = 11 So, x = 6 and y = 2 |
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Hence, x2/yz = 36/22 = 18/11 |