If x + y + z = 4, xy + yz + zx = 1 and x3 + y3 + z3 = 34, then what is the value of 6xyz?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. -36.
\begin{align*} 34 &= 4^3 - 3(4)(1) + 3xyz \\ 34 &= 64 - 12 + 3xyz \\ 34 &= 52 + 3xyz \\ 3xyz &= 34 - 52 = -18 \\ 6xyz &= 2 \cdot (-18) = \boxed{-36} \end{align*}