If x + y + z = 13, x2 + y2 + z2 = 133, and x3 + y3 + z3 = 847, then the value of 3√xyz is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. -6.
We know that,
x3 + y3 + z3 - 3xyz = (x + y + z)(x2 + y2 + z2 - (xy + yz + zx)).........(1)
(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)...........(2)
Now, according to the question
From Equation (2)
⇒ 132 = 133 + 2(xy + yz + zx)
⇒ 169 - 133 = 2(xy + yz + zx)
⇒ (xy + yz + zx) = 36/2
⇒ (xy + yz + zx) = 18
Put all the values in Equation (1);
x3 + y3 + z3 - 3xyz = (x + y + z)(x2 + y2 + z2 - (xy + yz + zx))
⇒ 847 - 3xyz = 13(133 - 18)
⇒ 847 - 115 × 13 = 3(xyz)
⇒ - 648 = 3(xyz)
⇒ - 216 = xyz
⇒ - (216)1/3 = (xyz)1/3
⇒ - (216)1/3 = 3√xyz
So, the value of 3√xyz = - 6