If x + y + z = 1, xy + yz + zx = – 26 and x3 + y3 + z3 = 151 then what will be the value of xyz?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 24.
Given:
x + y + z = 1, xy + yz + zx = – 26 and
x3 + y3 +z3 = 151
Use the formula:
(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)
And
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – (xy + yz + zx))
Using formula:
12 = x2 + y2 + z2 + 2 × -26
x2 + y2 + z2 = 53
And
151 – 3xyz = 1 × (53 – (-26))
3xyz = 151 – 79 = 72
xyz = 24