If x + y + z = 0, then the value of (x2 + y2 + z2) ÷ (z2 – xy) is:
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. 2
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Concept |
Understanding |
Application |
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x2 + y2 = (x + y)2 – 2xy |
Given: (x + y + z) = 0 Or (x + y) = -z |
(x2+ y2 + z2) ÷ (z2 – xy) ⇒((x + y)2 – 2xy + z2) ÷ (z2 – xy) Put (x + y) = -z ⇒(z2 – 2xy + z2) ÷ (z2 – xy) ⇒ 2(z2 – xy) ÷ (z2 – xy) ⇒ 2 |