If x-y+z = 0, then find the value of (y²)/2xz - (x²)/2yz - (z²)/2xy

If x-y+z = 0, then find the value of (y²)/2xz - (x²)/2yz…

If x-y+z = 0, then find the value of $\frac{y^2}{2xz}$ - $\frac{x^2}{2yz}$ - $\frac{z^2}{2xy}$

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. $\frac{3}{2}$

If x - y + z = 0, then let us assume that x = 1 , y = 2 and z = 1

$\frac{y^2}{2xz}$ - $\frac{x^2}{2yz}$ - $\frac{z^2}{2xy}$ = 4/2 - 1/4 - 1/4 = 2 - 1/4 - 1/4 = 2 - 1/2 = 3/2