SSC Selection Post 2022 PYQ — Question 58

SSC Selection Post - Graduation Level - 8 Feb 2022 - Shift 3 • Quantitative Aptitude • Q58

If x - y = 79{7 \over 9} and 1x−1y=1012{1 \over x} - {1 \over y} = 10{1 \over 2} , then what is the value of (x3 – y3)?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 217729{217 \over 729}.

​​1x−1y=1012=212{1 \over x} - {1 \over y} = 10{1 \over 2} =\frac{21}{2}

⇒ y−xxy=212\frac{y - x}{xy} = \frac{21}{2}

⇒ −79xy=212\frac{-\frac{7}{9}}{xy} = \frac{21}{2}

⇒ xy=−227 xy = -\frac{2}{27}

x2 + y2 = (x - y)2 + 2xy = (7/9)2 + 2(-2/27) = 49/81 - 4/27 = 37/81

x3 - y3 = (x - y)(x2 + xy + y2)

= (7/9)(37/81 -2/27)

= (7/9)(31/81)

= 217/729