SSC CHSL 2019 PYQ — Question 71

SSC CHSL - 1st July 2019 - Shift 3 • Quantitative Aptitude • Q71

If x + y = 7 and xy = 10, then the value of (1/x3 + 1/y3) is:

Show answer & explanation

Correct answer: B

Explanation

Correct Answer is option 2 i.e. 0.133

Concept

Understanding

Application

Fair calculation

x3 + y3 = (x + y) (x2 + y2 – xy)

 

Given

x + y = 7

xy = 10

1/x3 + 1/y3

= [x3 + y3]/x3y3

= [(x + y) (x2 + y2 – xy)]/x3y3

= [(x + y) ((x + y)2 – 3xy)]/x3y3

= [7((7)2 – 30)]/1000

= 133/1000

= 0.133

 

 

[7((7)2 – 30)]/1000

= [7(49 – 30)]/1000

= [7 × 19]/1000

= 133/1000

= 0.133