If X:Y = 3:2 then the value of 2x+5y3x+7y\frac{2x + 5y}{3x + 7y}3x+7y2x+5y ? A13 B14/25 C17/24 D16/23 Show answer & explanationCorrect answer: DExplanationx:y=3:2,x=3k, y=2k2x+5y3x+7y=2×3k+5×2k3×3k+7×2k=6k+10k9k+14k=16k23k=1623x : y = 3 : 2,\quad x = 3k,\; y = 2k\\ \frac{2x + 5y}{3x + 7y}\\ = \frac{2\times 3k + 5\times 2k}{3\times 3k + 7\times 2k}\\ = \frac{6k + 10k}{9k + 14k}\\ = \frac{16k}{23k}\\ = \frac{16}{23}x:y=3:2,x=3k,y=2k3x+7y2x+5y=3×3k+7×2k2×3k+5×2k=9k+14k6k+10k=23k16k=2316