SSC CHSL 2020 PYQ — Question 52

SSC CHSL - 14th October 2020 - Shift 2 • Quantitative Aptitude • Q52

If x + y = 14; x3 + y3 = 1064, then the value of (x – y)2 is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e 46.

Understanding Application

(x3 + y3) = (x + y)( x2 + y2 - xy)

( x - y )2 = ( x2 + y2 - 2xy)

(x3 + y3) = (x + y)( x2 + y2 - xy) = (x + y)( x2 + y2 - xy + xy - xy ) = (x + y)( x2 + y2 - 2xy + xy)

1064 = 14 { (x - y)2 + xy}

76 = (x - y)2 + xy =(x - y)2 +30

(x - y)2  = 76 - 30 = 46