SSC CGL 2024 PYQ — Question 61

SSC CGL - 25 Sep 2024 - Shift 2 • Quantitative Aptitude • Q61

If x = p secA cosB, y = q secA sinB, and z = r tanA, what is the value of x2p2+y2q2−z2r2\frac{x^2}{p^2}+\frac{y^2}{q^2}-\frac{z^2}{r^2}?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 1.

x = p secA cosB, y = q secA sinB, and z = r tanA

The value of x2p2+y2q2−z2r2\frac{x^2}{p^2}+\frac{y^2}{q^2}-\frac{z^2}{r^2} 

⇒ (psecAcosB)2p2+(qsecAsinB)2q2−(rtanA)2r2\frac{(p secA cosB)^2}{p^2}+\frac{(q secA sinB)^2}{q^2}-\frac{(r tanA)^2}{r^2}

⇒ p2sec2Acos2Bp2+q2sec2Asin2Bq2−r2tan2Ar2\frac{p^2 sec^2A cos^2B}{p^2}+\frac{q^2 sec^2A sin^2B}{q^2}-\frac{r^2 tan^2A}{r^2}

⇒ sec2A cos2B + sec2A sin2B - tan2A    [cos2A + sin2A = 1]

⇒ sec2A (cos2B + sin2B) - tan2A

⇒ sec2A - tan2A = 1