If x and y are real numbers, the the least possible value of 4(x – 2)2 + (y – 3)2 – 2 (x – 3)2 is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. –4
| Understanding | Application |
| Tricks |
Since we have to find the least value So here only one condition when we got a negative value i.e. 4 (x - 2)2 – 2 (x – 3)2 can give me negative |
| Now |
put x = 1 & y = 3 = 4(x – 2)2 + (y – 3)2 – 2 (x – 3)2 = 4(1 – 2)2 + (3 – 3)2 – 2 (1 – 3)2 = 4 + 0 – 8 = -4 |