SSC CGL 2022 PYQ — Question 69

SSC CGL - 02 Dec 2022 - Shift 1 • Quantitative Aptitude • Q69

If x=5−25+2x = {\sqrt{5} -2\over \sqrt{5} +2}, then the value of x2 + x-2 is :

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Correct answer: D

Explanation

The correct answer is option 4 i.e. 322.

Formula used:

(a + b)2 = a2 + b2 + 2ab           ---- (1)

Calculations:

⇒ x=5−25+2×5−25−2x = {\sqrt{5} -2\over \sqrt{5} +2}\times\frac{\sqrt5-2}{\sqrt5-2} 

⇒ x=(5−2)252−22x = \frac{(\sqrt5 - 2)^2}{\sqrt5^2 - 2^2}

⇒ x = 9 - 4√5

⇒ 1/x = 9 + 4√5

⇒ x + 1/x = 9 - 4√5 + 9 + 4√5 = 18

Using the equation (1), we get

⇒ (18)2 = x2 + x-2 + 2

⇒ x2 + x-2 = 324 - 2 = 322