SSC CHSL 2023 PYQ — Question 52

SSC CHSL 2023 - 04 Aug 2023 - Shift 2 • Quantitative Aptitude • Q52

If x + 2x=1\frac{2}{x}=1, then the value of x2+7x+2x2+13x+2\frac{x^2+7x+2}{x^2+13x+2} is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 47\frac{4}{7}.

Given that, x + 2x=1\frac{2}{x}=1

According to the given question,

x2+7x+2x2+13x+2\frac{x^2+7x+2}{x^2+13x+2}

⇒ x(x+7+2x)x(x+13+2x)\frac{x(x+7+\frac{2}{x})}{x(x+13+\frac{2}{x})}

⇒ (1+7)(1+13)\frac{(1+7)}{(1+13)}

⇒ 814\frac{8}{14} = 47\frac{4}{7}

Hence the required answer is 47\frac{4}{7}.