SSC CGL 2024 PYQ — Question 63

SSC CGL - 10 Sep 2024 - Shift 2 • Quantitative Aptitude • Q63

If x\sqrt x + 1x1\over{\sqrt x} = 7, then the value of x + 1xx\ +\ {1\over x} is equal t8o:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 47.

We know that,

(a + b)2 = a2 + b2 + 2ab

x\sqrt x + 1x1\over{\sqrt x} = 7

Squaring both sides

⇒ (x\sqrt x + 1x1\over{\sqrt x})2 = 72

⇒ (x\sqrt x)2 + (1x1\over{\sqrt x})2 + 2 × 1x1\over{\sqrt x} × x\sqrt x = 49

⇒ x + 1x1\over{x} + 2 = 49

⇒ x + 1x1\over{x} = 47