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SSC CGL 2017 PYQ — Question 71

SSC CGL Tier II Quant - 12/01/2017 • Quantitative Aptitude • Q71

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If x = 11, the value of x5 – 12x4 + 12x3 – 12x2 + 12x – 1 is:

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Correct answer: B

Explanation

  The correct answer is option 2 i.e. 10

Application

x5 – 12x4 + 12x3 – 12x2 + 12x – 1

⇒ x5 – 11x4 – x4 + 11x3 + x3 – 11x2 – x2 + 11x + x – 1

⇒ x4(x – 11) – x3(x – 11) + x2(x – 11) – x(x – 11) + (x – 1)

x = 11, then

⇒ 0 + 0 + 0 + 0 + (11 – 1)

⇒ 10