SSC CHSL 2021 PYQ — Question 58

SSC CHSL - 16 April 2021 - Shift 2 • Quantitative Aptitude • Q58

If x+1x=7x+\frac{1}{x}=7, then x3+1x2x^3+\frac{1}{x^2} is equal to:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 322

If x+1x=7x+\frac{1}{x}=7

Cube on both sides

x3+1x2x^3+\frac{1}{x^2} = 73 - 3 *7 = 343 - 21 = 322