SSC CHSL 2023 PYQ — Question 56

SSC CHSL - 02 Aug 2023 - Shift 1 • Quantitative Aptitude • Q56

If x + 1x\frac{1}{x} = 7 , Then the value of x2 + 1x2\frac{1}{x^2} is :

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 47.

Given that

If x + 1x\frac{1}{x} = 7 ,

Square both sides

⇒ (x + 1x\frac{1}{x})2 = 72

 ⇒ x2 + 1x2\frac{1}{x^2} + 2 = 49

⇒  x2 + 1x2\frac{1}{x^2} = 49 - 2 = 47