SSC CHSL 2020 PYQ — Question 73

SSC CHSL - 20th October 2020 - Shift 2 • Quantitative Aptitude • Q73

If x + (1/x) = 5, x ≠ 0, then the value of (x4 + 1/x2)/(x2 - 3x + 1) is equal to:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 55.

Understanding/Application

x + 1/x = 5 

(x4 + 1/x2)/(x2 - 3x + 1)

= [x(x3 + 1/x3)]/[x(x - 3 + 1/x)]

= (x3 + 1/x3)/(x - 3 + 1/x)

= [(x + 1/x)3 - 3(x + 1/x)]/5 - 3

= (125 - 15)/2

= 110/2

= 55