SSC CHSL 2023 PYQ — Question 54

SSC CHSL - 07 Aug 2023 - Shift 4 • Quantitative Aptitude • Q54

If (x−1x−2)=7(x-\frac{1}{x-2})=7, then the value of (x - 2)3 - 1(x−2)3\frac{1}{(x-2)^3} is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 140.

(x−1x−2)=7(x-\frac{1}{x-2})=7

Let, y = x - 2

So,

⇒ (y+2−1y+2−2)=7(y+2-\frac{1}{y+2-2})=7

⇒ (y+2−1y)=7(y+2-\frac{1}{y})=7

⇒ y - 1y1\over y = 5

Now,

⇒ (y - 1y1\over y)3 = y3 - 1y31\over y^3 - 3(y - 1y1\over y)

⇒ 53 = y3 - 1y31\over y^3- 3(5)

⇒ y3 - 1y31\over y^3 = 125 + 15

⇒ y3 - 1y31\over y^3 = 140

Thus, the value of (x - 2)3 - 1(x−2)3\frac{1}{(x-2)^3} is 140