SSC CHSL 2021 PYQ — Question 66

SSC CHSL - 6 Aug 2021 - Shift 3 • Quantitative Aptitude • Q66

If x - 1x=22\frac{1}{x}=2\sqrt{2}, then what will be the value of x3 - 1x3\frac{1}{x^3}?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 222\sqrt{2}

Given:

 x - 1x=22\frac{1}{x}=2\sqrt{2}

Formula USed:

(a - b)3 = a3 - b3 - 3ab(a - b)

Explanation:

According to the given question,

 x - 1x=22\frac{1}{x}=2\sqrt{2}

Taking cube on both sides, we get

( x - 1x)3=(22\frac{1}{x})^3=(2\sqrt{2})3

⇒ x3 - 1x3\frac{1}{x^3} - 3(1)(22\sqrt{2}) = 162\sqrt{2}

⇒ x3 - 1x3\frac{1}{x^3} - 62\sqrt{2} = 162\sqrt{2}

 ⇒ x3 - 1x3\frac{1}{x^3} = 222\sqrt{2}

Hence the required answer is 222\sqrt{2}.