SSC Selection Post 2025 PYQ — Question 36

SSC Selection Post - Graduation Level - 25th July 2025 - Shift 3 • Quantitative Aptitude • Q36

If x + 1/(x + 1) = 6, then determine the value of (x + 2)³ + 1/(x + 2)³.

Show answer & explanation

Correct answer: A

Explanation

x + 1/(x + 1) = 6

Let – y = x + 1

y + 1/y = 6

y² + 1 = 6y

y² − 6y + 1 = 0

y = 3 ± 2√2

y + 1 = 4 ± 2√2

a³ + b³ = (a + b)³ − 3ab(a + b)

a = y + 1

b = 1/(y + 1)

ab = 1

a + b = (y + 1) + 1/(y + 1)

= [(y + 1)² + 1]/(y + 1)

= (y² + 2y + 2)/(y + 1)

y² = 6y − 1

a + b = (6y − 1 + 2y + 2)/(y + 1)

= (8y + 1)/(y + 1)

Putting y = 3 + 2√2 -

a + b = 8

a³ + b³ = 8³ − 3×1×8

= 512 – 24 = 488