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SSC Selection Post 2024 PYQ — Question 69

SSC Selection Post - Graduation Level - 24 June 2024 - Shift 3 • Quantitative Aptitude • Q69

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If (x−1x−1)=3( x - \frac{1}{x-1}) = 3, then the value of (x−1)2+1(x−1)2(x - 1)^2 + \frac{1}{(x-1)^2 } is :

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 6.

(x−1x−1)=3( x - \frac{1}{x-1}) = 3

⇒ (x−1)−1(x−1)=2( x-1) - \frac{1}{(x-1)} = 2

⇒ (x−1)2+1(x−1)2=22+2=6(x - 1)^2 + \frac{1}{(x-1)^2 }=2^2+2= 6