SSC CGL 2023 PYQ — Question 66

SSC CGL - 20 July 2023 - Shift 4 • Quantitative Aptitude • Q66

If x+1xx + {1 \over x} =323 \sqrt{2}, and x > 1, what is the value of (x8 - 1x81 \over x^8) ?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e.  243847\sqrt{7}.

Given that

 x+1xx + {1 \over x} =323 \sqrt{2}

(x8 - 1x81 \over x^8) = (x4 + 1x41 \over x^4)(x2 - 1x21 \over x^2)(x2 + 1x21 \over x^2)         ...........1

⇒ (x+1xx + {1 \over x})2 =  (x2 - 1x21 \over x^2) = (323 \sqrt{2})2 - 2 = 16

⇒  (x2 - 1x21 \over x^2) = 16              .....2

Now squarying both sides

 (x2 - 1x21 \over x^2)2 = 162

⇒ x4 + 1x41 \over x^4 = 256 - 2 = 254          .....3

Now

x4 + 1x41 \over x^4 - 2 = 254 - 2

⇒ (x2 - 1x21 \over x^2)2 = 252

⇒ (x2 - 1x21 \over x^2) = 67\sqrt7                 ..........4

Put the value of equations 2, 3, and 4 in equation 1

(x8 - 1x81 \over x^8) = 254 × 67\sqrt7 × 16 = 243847\sqrt7