If two tangents to a circle of radius 3 cm are inclined to each other at angle of 60°, then the length of each tangent is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. .

Let PQ and PR be the tangents drawn to a circle
Now, according to the question
⇒ √RPQ = 60°
So, QP = RP
in △PQO and △PRO
⇒ QP = RP
⇒ QO = RO [radius]
⇒ PO = PO [common side]
△PQO and △PRO are similar by SSS criterion
At the point of contact, the radius of a circle is perpendicular to the tangent
So, √PQO = √PRO = 90°
Since, QO = RO = radius
⇒ √PQO = √PRO
⇒ √RPO = √PQO + √PRO
⇒ 2√PQO = 60°
⇒ √PQO = 60°/2 = 30°
In △PQO
PQO is a right triangle with A at right angle
⇒ tan 30° = QO/PQ
⇒ 1/√3 = 3/QP
⇒ QP = 3√3 cm
Thus, the length of each tangent is 3√3 cm