SSC CHSL 2024 PYQ — Question 64

SSC CHSL - 04 July 2024 - Shift 2 • Quantitative Aptitude • Q64

If two numbers are each divided by the same divisor, then the remainder are 6 and 7, respectively. If the sum of the two numbers be divided by the same divisor, then the remainder is 5. The divisor is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 8.

Let the divisor be D, and the two numbers be a and b.

When a is divided by D, the remainder = 6

⇒ a = kD + 6 for some integer k

When b is divided by D, the remainder = 7

⇒ b = mD + 7 for some integer m

The sum of the two numbers = a + b = kD + 6 + mD + 7 = (k + m)D + 13

When a + b is divided by D, the remainder = 5

Remainder of 13 divided by D = 5

This means

⇒ 13 − 5 = 8 is divisible by D

The divisors of 8 are (D) = 1, 2, 4, 8

Since the value of D must be greater than the largest remainder (7),

the only valid value D = 8