SSC CGL 2024 PYQ — Question 71

SSC CGL - 18 Sep 2024 - Shift 1 • Quantitative Aptitude • Q71

If three cubes of volume 512 cm3 each are joined end to end, find the surface area of the resulting cuboid.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 896 cm2.

Volume of each cube = 512 cm3

We know that,

The volume of the cube = a3

⇒ a3 = 512

⇒ a = ∛512

⇒ a = 8 cm

When three cubes are joined end to end, the dimensions of the cuboid

Length(l) = 8 + 8 + 8 = 24 cm

Breadth(b) = 8 cm

Height(h) = 8 cm

Now,

The surface area of a cuboid(A) = 2(lb + bh + hl)

⇒ A = 2(24 × 8 + 8 × 8 + 8 × 24)

⇒ A = 2(192 + 64 + 192)

⇒ A = 2 × 448

⇒ A = 896 cm3