If the value of (a+b-3)2+(b+c-2)²+(c+a-5)²=0, then the value of is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 3.
(a + b − 3)2 + (b + c − 2)2 + (c + a − 5)2 = 0
⇒ a + b = 3, b + c = 2, c + a = 5
b = 0, a = 3, c = 2
√[(b + c)a + (c + a)b]
= √[(0 + 2)3 + (2 + 3)0]
= √[23 + 50] = √[8 + 1] = √9 = 3