If the six-digit number 15x1y2 is divisible by 44, then the minimum value of (x + y) is equal to:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 7.
Divisibility rule for 44: Must be divisible by both 4 and 11
The last two digits (y2) must be divisible by 4
Possible values for y: 1, 3, 5, 7, 9
Alternating sum: (1 + x + y) - (5 + 1 + 2) = (x + y - 7) must be divisible by 11
For x = 6 and y = 3 → x + y = 7
154132 ÷ 44 = 3503 (Divisible)
Hence, the minimum value of (x + y) is 7.