If the radius of a sphere is increased by 125%, then by what percentage will its surface area increase (correct to two decimal places)?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e 406.25%.
Let the initial radius of the sphere be r
When the radius is increased by 125%, the new radius becomes:
rnew = r + 1.25r = 2.25r
The surface area of the sphere = 4πr2
New surface area = Snew = 4π × 5.0625r2
⇒ 20.25πr2
Thus,
Percentage increase = (Snew - S)/S × 100
⇒ (20.25πr2 - 4πr2)/4πr2 × 100
⇒ 16.25πr2/4πr2 × 100
⇒ 406.25%
So, the surface area will increase by 406.25%