If the radius of a sphere is increased by 40%, then find the percentage increase in its surface area.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 96%.
Given that
The radius of the sphere is increased by 40%
Let the old radius be R
Hence, the new radius is 1.4R
Formula used
Surface area of sphere = 4πr2
Let the old surface area be A
⇒ A = 4πR2
New surface area A' = 4π( 1.4R × 1.4R )2 = 1.96 × 4πR2 = 1.96A
Hence percentage increase = × 100 = 96%